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105
tests/test_dictionary.py
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105
tests/test_dictionary.py
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import pytest
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from multiplayer_crosswords.dictionary import Word, Dictionary
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def test_add_word_and_to_dict():
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d = Dictionary()
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w = Word("apple", ["a red or green fruit"], 0.2)
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d.add_word(w)
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result = d.to_dict()
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assert "words" in result
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assert len(result["words"]) == 1
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assert result["words"][0]["word"] == "apple"
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assert result["words"][0]["hints"] == ["a red or green fruit"]
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assert result["words"][0]["difficulty"] == 0.2
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def test_from_dict_and_to_dict_roundtrip():
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data = {
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"words": [
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{"word": "banana", "hints": ["a yellow fruit", "something monkeys like to eat"], "difficulty": 0.1},
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{"word": "car", "hints": ["vehicle", "four wheels"], "difficulty": 0.3}
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]
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}
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d = Dictionary.from_dict(data)
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assert len(d.words) == 2
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assert d.words[0].word == "banana"
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assert d.words[1].hints == ["vehicle", "four wheels"]
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assert d.words[1].difficulty == 0.3
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assert d.to_dict() == data
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def test_to_json_and_from_json():
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d = Dictionary()
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d.add_word(Word("dog", ["animal", "barks"], 0.15))
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json_str = d.to_json()
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d2 = Dictionary.from_json(json_str)
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assert len(d2.words) == 1
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assert d2.words[0].word == "dog"
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assert d2.words[0].hints == ["animal", "barks"]
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assert d2.words[0].difficulty == 0.15
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def test_empty_dictionary_to_dict_and_json():
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d = Dictionary()
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assert d.to_dict() == {"words": []}
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json_str = d.to_json()
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assert json_str.strip().startswith("{")
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d2 = Dictionary.from_json(json_str)
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assert isinstance(d2, Dictionary)
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assert d2.words == []
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def test_word_to_dict_and_from_dict():
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w = Word("cat", ["animal", "meows"], 0.12)
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d = w.to_dict()
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assert d == {"word": "cat", "hints": ["animal", "meows"], "difficulty": 0.12}
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w2 = Word.from_dict(d)
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assert w2.word == "cat"
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assert w2.hints == ["animal", "meows"]
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assert w2.difficulty == 0.12
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def test_find_by_pattern_exact_match():
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d = Dictionary()
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d.add_word(Word("apple", ["fruit"], 0.2))
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d.add_word(Word("apply", ["verb"], 0.3))
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d.add_word(Word("angle", ["geometry"], 0.4))
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result = d.find_by_pattern("apple")
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assert [r.word for r in result] == ["apple"]
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def test_find_by_pattern_with_wildcards():
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d = Dictionary()
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d.add_word(Word("apple", ["fruit"], 0.2))
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d.add_word(Word("apply", ["verb"], 0.3))
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d.add_word(Word("angle", ["geometry"], 0.4))
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d.add_word(Word("ample", ["enough"], 0.5))
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# Pattern: a**le should match apple and angle and ample
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result = sorted([w.word for w in d.find_by_pattern("a**le")])
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assert set(result) == {"apple", "angle", "ample"}
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def test_find_by_pattern_all_wildcards():
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d = Dictionary()
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d.add_word(Word("apple", ["fruit"], 0.2))
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d.add_word(Word("apply", ["verb"], 0.3))
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d.add_word(Word("angle", ["geometry"], 0.4))
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# Pattern: ***** should match all 5-letter words
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result = sorted([w.word for w in d.find_by_pattern("*****")])
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assert set(result) == {"apple", "apply", "angle"}
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def test_find_by_pattern_no_match():
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d = Dictionary()
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d.add_word(Word("apple", ["fruit"], 0.2))
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d.add_word(Word("apply", ["verb"], 0.3))
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# Pattern: z**** should match nothing
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result = d.find_by_pattern("z****")
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assert list(result) == []
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def test_find_by_pattern_duplicate_letters():
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d = Dictionary()
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d.add_word(Word("level", ["word"], 0.1))
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d.add_word(Word("lever", ["tool"], 0.2))
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# Pattern: l*vel should match "level" only
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result = d.find_by_pattern("l*vel")
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assert [r.word for r in result] == ["level"]
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def test_find_by_pattern_length_not_in_index():
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d = Dictionary()
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d.add_word(Word("cat", ["animal"], 0.1))
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# Pattern: four letters, but only 3-letter word in dict
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result = d.find_by_pattern("****")
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assert [r.word for r in result] == []
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